Does one cast a copy of a spell?

Asked by Femme_Fatale 9 years ago

Basically my issue is this: Casting a Grapeshot with a Jeskai Ascendancy on the field. Do all the copies of grapeshot that are being made get cast, or do they just "appear on the stack"? I'm worried that Jeskai Ascendancy may occasionally deck me out before I kill them with Grapeshot .

Epochalyptik says... Accepted answer #1

Always check the Gatherer rulings before asking a question.

6/7/2013: The copies are put directly onto the stack. They aren't cast and won't be counted by other spells with storm cast later in the turn.

A copy of a spell is never cast. A copy of a card that isn't on the stack is cast only if you are instructed to cast it.

October 7, 2014 3:35 p.m.

Femme_Fatale says... #2

Gatherer is being derpy for me today, but thanks anyways~

October 7, 2014 3:36 p.m.

Gidgetimer says... #3

Epochalyptik answered your specific question, but the answer to the question in the title is: it depends on what the effect creating the spell says.

Cipher spells, Isochron Scepter , and Chandra, Pyromaster have you cast the copies of spells they make. Storm spells, Conspire spells, and Chandra, the Firebrand create the copies on the stack and they were never cast.

October 7, 2014 4:18 p.m.

Epochalyptik says... #4

@Gidgetimer: See the last note in my reply.

Generally speaking, effects that tell you to copy a spell (i.e. a card or copy of a card on the stack) do not instruct you to cast the copy because the copy is created in the same zone as the original object. In this case, that means the copy is created on the stack as a spell, so it doesn't need to be cast.

If an effect tells you to create a copy of a card in another zone (usually exile), then it will instruct you to cast the copy because it is not yet on the stack.

October 7, 2014 4:21 p.m.

kanofudo says... #5

finally Jeskai Ascendancy 's draw ability is a may. it can't deck you.

October 7, 2014 8:31 p.m.

Femme_Fatale says... #6

Herpa derpa derpa herp.

October 7, 2014 10:25 p.m.

This discussion has been closed